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A chord of a circle of radius 30 cm makes an angle of 60° at the centre of the circle. Find the area of the minor and major segments.

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Let AB be the chord of a circle with centre O and radius 30 cm such that ∠AOB = 60°

Area of the minor segment = (Area of the sector OACBO) - (Area of ΔOAB)

= (471 - 389.7) cm

= 81.3 cm2

Area of the major segment =(Area of the circle) - (Area of minor segment)

= |(3.14 x 30 x 30) - 81.3| cm2

= 2744.7 cm2

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