**Let AB be the chord of a circle with centre O and radius 30 cm such that ∠AOB = 60°**

**Area of the minor segment = (Area of the sector OACBO) - (Area of ΔOAB)**

= (471 - 389.7) cm^{2 }

= 81.3 cm^{2}

**Area of the major segment =(Area of the circle) - (Area of minor segment)**

= |(3.14 x 30 x 30) - 81.3| cm^{2}

= 2744.7 cm^{2}