Question

A chord of a circle of radius 30 cm makes an angle of 60° at the centre of the circle. Find the area of the minor and major segments.

Answer 1

Let AB be the chord of a circle with centre O and radius 30 cm such that ∠AOB = 60°

Area of the minor segment = (Area of the sector OACBO) - (Area of ΔOAB)

= (471 - 389.7) cm² 

= 81.3 cm²

Area of the major segment =(Area of the circle) - (Area of minor segment)

= |(3.14 x 30 x 30) - 81.3| cm²

= 2744.7 cm²