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+1 vote
30.9k views
in Physics by (51.7k points)

Playing with an old lens one morning, Ravi discovers that if he holds the lens 10 cm away from a wall opposite to a window, he can see a sharp but upside-down picture of outside world on the wall. That evening, he covers a lighted lamp with a piece of opaque paper on which he has pierced, a small hole I mm in diameter. By placing the lens between the illuminated card and the wall, he manages to produce a sharp image of diameter 5 mm on the wall.
Answer the following questions based on the above information:
(i) What is the power of the lens?
(ii) In the evening experiment, how far away from the opaque paper did he place the lens?
(iii) How far apart were the card and the wall?

1 Answer

+1 vote
by (266k points)
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Best answer

(i) Since the rays from far away object get focussed at the principal focus, distance between lens and wall is equal to focal length 10 cm.

 Power of the lens= +10 D.

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