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In a hydraulic lift, the input piston has surface area 20 cm2. The output piston has surface area 1000 cm2 . If a force of 50 N is applied to the input piston, it raises the output piston by 2 m. Calculate the weight of the support on the output piston and the work done by it.

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Data : A1 = 20 cm2 = 2 × 10-3 m2

A2 = 1000 cm2 = 10-1 m2 , F1 = 50 N, s2 = 2m

(i) By Pascal’s law,

This gives the weight of the support on the output piston.

(ii) The work done by the force transmitted to the output piston is 

F2S2 = (2500 N) (2 m) 

= 5000 J

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