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0 votes
1.7k views
in Physics by (32.6k points)
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A thin ring of diameter 8 cm is pulled out of water (surface tension 0.07 N/m). The force required to break free the ring from water is 

(A) 0.0088 N 

(B) 0.0176 N 

(C) 0.0056 N 

(D) 3.52 N.

2 Answers

+1 vote
by (67.5k points)
selected by
 
Best answer

Correct Option is (C) 0.0056 N

Given Diameter = 8 cm = 0.08 m

T = 0.07 N/M

Surface Tension \(T = \frac{F}{l}\)

F = T . l

\(F = 0.07 \times 0.08\)

F = 0.0056 N

+1 vote
by (32.8k points)
edited by

(C) 0.0056 N

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