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0 votes
2.9k views
in Physics by (32.7k points)
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The pressure difference across the surface of a spherical water drop of radius 1 mm and surface tension 0.07 N/m is 

(A) 28 Pa 

(B) 35 Pa 

(C) 140 Pa 

(D) 280 Pa.

2 Answers

+1 vote
by (67.5k points)
selected by
 
Best answer

Correct Option is (C) 140 Pa

R = 1 mm

S = 0.07

\(\Delta P = ?\)

Pressure difference \(\Delta P = \frac{25}{R}\)

\(= \frac{2 \times 0.07}{1 \times 10.3 }\)

\(\Delta P\) = 140 Pa

+1 vote
by (32.8k points)

Correct option is (C) 140 Pa

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