Correct Option is (C) 1 : 3
Given,
\(R_1 = 3\)
\(R_2 = 2\)
Pressure \(\Delta P_1 = \frac{4 S}{r_1}\)
Inside \(\Delta P_2 = \frac{8S}{R_2}\)
\(\frac{\Delta P_1}{\Delta P_2} = \frac{4S}{R_1} \times \frac{R_2}{8S}\)
\(= \frac{R_2}{2R_1}\)
\(\frac{\Delta P_1}{\Delta P_2} = \frac{2}{2 \times 3}\)
\(\frac{\Delta P_1}{\Delta P_2} = \frac{1}{3}\)
\(\Delta P_1 : \Delta P_2 = 1 : 3\)