Question

A fluid flows in steady flow through a pipe.

The pipe has a circular cross section, but its radius varies along its length. The mass of the fluid passing per second at the entrance point (radius R) of the pipe is Q₁ while that at the exit point (radius R/2) is Q₂. Then, Q is equal to

(A) \(\frac14\)Q₁

(B) Q₁ 

(C) 2Q₁ 

(D) 4Q₁

Answer 1

Correct option is (B) Q₁ 

Answer 2

We know that

A₁V₁ = constant

A₁V₁ = A₂V₂

\(\pi r^2_1Q_1=\pi r^2_2Q_2\)

\(R^2Q _1 =\frac{R^2}{4}Q _2\)

4Q₁ = Q₂