Correct Option is (D) \([ML^{-1}T^{-1}]\)
We know that ,
\(F = \eta A \left(\frac{dv}{dx}\right) \)
where,
F = Force
A = Area
\(\eta\) = cofficient of viscosity
dv = velocity change by dx
\(\eta = \frac{F}{A} \left(\frac{dx}{dv}\right)\)
\(\eta\) = \(\frac{[MLT^{-2}][L]}{[L^2][LT^{-1}]}\)
\(\eta = [ML^{-1}T^{-1}]\)