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in Chemical Bonding and Molecular Structure by (81.4k points)
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Smallest intenuclear distance is found in

(a) O2

(b) O22+

(c) O2-

(d) O22-

1 Answer

+1 vote
by (92.4k points)
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Best answer

Correct option  (b) O22+

Explanation:

In O2, the bond order = 2

In O22+, the bond order = 3

In O2- , the bond order= 1.5

In O22- , the bond order = 1

As the bond order in O22+ is highest, so its internuclear distance is smallest.

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