R = 8%, P = Rs. 16000, A = Rs. 32000
Let after n years Rohit will get money to double the value invested by him.
\(\because A=P(1+\frac R{100})^n\)
⇒ 32000 = 16000(1 + \(\frac{8}{100}\))n
⇒ (1 + \(\frac{2}{25}\))n = \(\frac{32000}{16000}=2\)
⇒ \((\frac{27}{25})^n=2\)
⇒ n log \(\frac{27}{25}\) = log 2
⇒ n = \(\frac{log2}{log1.08}\) = \(\frac{0.3010}{0.33423}\approx9\)
Almost, n = 9 years Rohit will double money as he invested.