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0 votes
asked in NEET by (2k points)
If two bulbs , whose resistances are in the ratio of 1:2 are connected  in series,  the power dissipated  in them has the ratio of

A) 2:1

B) 1:4

C) 1:1

D) 1:2

1 Answer

+1 vote
answered by (9.5k points)

Option (D)is correct


As the bulbs are joined in series we use the relation

Power= I2R

I is same for both the bulb

Hence P1:P2=R1:R2=1:2

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