Question

1 kg of ice at 0°C is mixed with 1 kg of steam at 100°C. Find the resultant temperature.

Answer 1

Compare latent heart of fusion of ice = 3.36 x 10⁵ J. Kg^-1

Latent heat of vaporization of water = 2.26 x 10⁶ J. Kg^-1

We see that steam will condense to become water at 100^oC and Ice will melt to become water at 0^o C

Hence in the final mixture we will have  water at  100^o C = 1.336 kg  and steam  99.664 kg  of steam.