Three ammeters `A,B`, and `C` of resistances `R_A,R_b` and `R_C` respectively are joined as shown. When some potential difference is appllied across the terminals `T_1` and `T_2` their readings are `I_A,I_B and I_C` respectively Then,
A. `I_A = I_B`
B. `I_A R_A + I_B R_B = I_C R_C`
C. `(I_A)/(I_C) = (R_C)/(R_A)`
D. `(I_B)/(I_C) = (R_C)/(R_A + R_B)`