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in Chemical Thermodynamics by (80.9k points)
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The enthalpy change (ΔH) for the reaction, N2(g)+3H2(g)2NH3(g) is -92.38 kJ at 298 K. The internal energy change (ΔU) at 298 K is

(a) -92.38 kJ

(b) -87.42 KJ

(c) -97 .34 kJ

(d) -89.9 kJ

1 Answer

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Best answer

Correct option  (b) -87.42 KJ

Explanation:

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