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The dissociation equilibrium of a gas AB, can be represented as

2AB2(g) ⇌ 2AB(g) +B2 (g)

The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure p is

(a) (2Kp/p)1/2

(b) kp/p

(c) 2kp/p

(d) (2kp/p)1/3

1 Answer

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Best answer

Correct option  (d) (2kp/p)1/3

Explanation:

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