Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.6k views
in Solid State by (79.0k points)
recategorized by

An element (atomic mass 100 g/mol) having bcc structure has unit cell edge 400 pm. The density of element is (No. of atom in bcc (Z) = 2).

(a) 2.144 g/cm3

(b) 7.289 g/cm3

(c) 5.188 g/cm3

(d) 10.376 g/cm3

1 Answer

+1 vote
by (50.7k points)
selected by
 
Best answer

Correct option  (c) 5.188 g/cm3

Explanation:

Atomic mass of element = 100 g/mol

Cell edge = 400 pm = 400 x 10-12 = 4 x 10-8 cm and number of atoms in bcc (Z) = 2

As the atomic mass of the metal is 100 g/mol,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...