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A forms hcp lattice and B arc occupying 1/3rd of tetrahedral voids, then the formula of compound is

(a) AB

(b) A3B3

(c) A2B3

(d) AB4 

1 Answer

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Best answer

Correct option (b) A3B3

Explanation:

Let no. of atoms of A  used in close packing = n

Number of tetrahedral voids = 2 n

Number of atoms of B = 1/3 x 2 n = 2/3 n

A :B = n :2/3 n = 3:2

Formula of the compound = A3B2

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