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A whistle giving out 450Hz approaches a stationary observer at a speed of 33m/s. The frequency heard by the observer in Hz is (speed of sound = 330m/s).

(a) 409

(b) 429

(c) 517

(d) 500

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Right option is (d) 500

The explanation: v^‘=v/(v-vs)×v

v^‘=330/(330-33)×450=500Hz.

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