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A 5% solution (by mass) of cane sugar in water has freezing point of 271 K and freezing point of pure water is 273.15 K. The freezing point of a 5% solution (by mass) of glucose in water is

(a) 271 K

(b) 273.15 K

(c) 269.07 K

(d) 277.23 K

1 Answer

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Best answer

Correct option (c) 269.07 K

Explanation:

:.  Freezing point of glucose solution = 273.15 - 4.08 = 269.07 K

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