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In Young’s Double Slit experiment, the angular width of the fringe is 0.1^o. If the light used has a wavelength of 600 nm, what is the spacing between the slits?

(a) 0.17 mm

(b) 0.23 mm

(c) 0.34 mm

(d) 0.49 mm

1 Answer

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Best answer
Right choice is (c) 0.34 mm

The best explanation: Now, as we know, β = λD/d

βθ = θn+1 – θn = β/D

βθ = λ/d

Here, λ = 6 X 10^-7 m and βθ = 0.1 X π/180 radians

Therefore, d = 6 X 10^-7 m X 180 = 0.1 X π

= 0.344 mm.

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