Question

The acceleration due to gravity on the surface of the Moon is 1.7 m/s² . What is the time-period of a simple pendulum on the Moon if its time period on the Earth is 3.5 s?

 (g on Earth = 9.8 m/s²)

Answer 1

We are given that time period of a simple pendulum on Earth, i.e., T_E = 3.5 s

Acceleration due to gravity on Earth, i.e., g_E = 9.8 m/s² 

Acceleration due to gravity on Moon, i.e., g_M = 1.7 m/s²

Let T_M be the time period of the simple pendulum on Moon. Clearly,