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Ferric oxide crystallizes in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

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Let the number of oxide (O2−) ions be x.

So, number of octahedral voids = x

It is given that two out of every three octahedral holes are occupied by ferric ions.

So, number of ferric (Fe3+) ions =2/3x

Therefore, ratio of the number of Fe3+ ions to the number of O2 ions,

Fe3+ : O2- = 2/3 x : x

Hence, the formula of the ferric oxide is Fe2O3.

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