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+1 vote
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in Mathematics by (130k points)
Find the equation of the tangent to the curve y =√(3x-2) which is parallel to the line 4x − 2y + 5 = 0.

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The equation of the given curve is y=√(3x-2.)

The slope of the tangent to the given curve at any point (x, y) is given by,

The equation of the given line is 4x − 2y + 5 = 0.

∴Slope of the line = 2
Now, the tangent to the given curve is parallel to the line 4x − 2y − 5 = 0 if the slope of the tangent is equal to the slope of the line.

Hence, the equation of the required tangent is 48x-24y =23

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