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(1+tanA+cotA)(sinA-cosA)/sec^3A-cosec^3A=sin^2A.cos^2A

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(1+tanA+cotA)(sinA-cosA)/sec3A-cosec3A=sin2A.cos2A

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1 Answer

+2 votes
by (10.9k points)

Here is the solution

LHS =

=RHS

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