Join Sarthaks eConnect Today - Largest Online Education Community!
+1 vote
asked in NEET by (2.2k points)

A particle in a certain conservative  force field has a p.e u= 20xy/ z . The force exerted  on it 

Ans - ( 20y/z) icap - (20x/z )jcap +( 20xy / z2 )kcap

commented by (14.6k points)
@shradha, This is a request that if you find my answer helpful please mark it as best answer and also up vote it.
commented by (2.2k points)
You andYour answer  is always  best  .  I had always vote u  from the initials  days.... dear......

1 Answer

+1 vote
answered by (14.6k points)
selected by
Best answer

Key concept to solve this:

Potential Energy Function:  If a force acting on an object is a function of position only, it is said to be a conservative force, and it can be represented by a potential energy function which for a one-dimensional case satisfies the derivative condition

-dU/dx = F(x)

We have given U = 20xy/ z

Now taking the derivative of U w.r.t x,y and z we get,

Fx = -20y/z, Fy = -20x/z, and Fz = 20xy/z2

Now adding all we get the final force, i.e

F = -(20y/z)i-(20x/z)j+(20xy/z2)k.

commented by (2.2k points)
Thanks for the crystal clear answer.  All the very best my best wishes  with you . You will achieve  great success  in your   life..
commented by (14.6k points)
Thanks for the best wishes and I wish the same for you:)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon