Question

Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^-1.

Answer 1

0.375 M aqueous solution of sodium acetate means that 1000 mL of solution containing 0.375 moles of sodium acetate. 

∴No. of moles of sodium acetate in 500 mL 

= (0.375/1000)×500 = 0.375/2 = 0.1875) 

Molar mass of sodium acetate = 82.0245g mol^-1 

∴Mass of sodium acetate acquired 

= 0.1875 x 82.0245 g = 15.380g