Question

Two positive point charges repel each other with force 0.36 N when their separation is 1.5 m. What force do they exert on each other when their separation is 1.0 m?

(A) 0.81 N 

(B) 0.54 N 

(C) 0.36 N 

(D) 0.24 N 

(E) 0.16 N

Answer 1

As we know that,

F₁ = 0.36 N

r₁ = 1.5 m

r₂ = 1.0 m

F ∝ 1/r² 

\(\frac{F_1}{F_2}= \frac{r{_2^2}}{r{_1^2}}\\\frac{0.36}{F_2} = \frac{1^2}{1.5^2}\\0.36 \times (1.5)^2= F_2\times(1.0)^2\\0.36\times 2.25=1F_2\\F_2= \frac{0.36\times2.25}{1}\\=0.81\)

Answer 2

The correct option is: (A) 0.81 N

Explanation:

F ∝ 1/r²

Comments

Calculations pls

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Plz see above