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0 votes
2.2k views
in Electrostatics by (80.8k points)
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How much work would be required to move a 4 coulomb charge 6 meters parallel to a 24 N/C electric field?

(A) 0 J 

(B) 24 J 

(C) 96 J 

(D) 144 J 

(E) 576 J

2 Answers

+1 vote
by (10.9k points)
selected by
 
Best answer
Option(E) is correct

Explanation

Workdone(W)= force(f)× displacement(d)

= Charge(q)×intensiy of Electric field (E)×displacement(d)

Here q= 4C,E=24N/C ,d =6m

So W = 4×24×6 J= 576J
+1 vote
by (52.5k points)

The correct option is: (E) 576 J

Explanation:

W = Fd = qEd

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