Question

Give reasons:

(a) Be has higher IP than B. 

(b) F has less negative EGE than Cl.

Answer 1

IP of Be is more than that of B.

Explanation: Be (Z=4) 1s²2s²       B(Z=5) – 1s²2s2²p¹

As the penetration effect on s is more than that on p so it is difficult to remove the electron from s orbital and therefore IP of Be is more than that of B.

(b) Due to very small size of F electron density around the nucleus is very high. 

Incoming electron experiences an interelectronic repulsion. To add this electron some positive energy is required and hence EGE of F becomes less negative than that of Cl.