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Consider the compounds CCl4, BCl3 and explain their behaviour with water.

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Consider the compounds CCl4, BCl3 and explain their behaviour with water.

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Being a Lewis acid, BCl3 readily undergoes hydrolysis. Boric acid is formed as a result.

BCl3+3H2O→3HCl+B(OH)3

CCl4 completely resists hydrolysis. Carbon does not have any vacant orbital. Therefore, it cannot accept electrons from water to form an intermediate. Separate layers are formed when CCl4 and water are mixed.

CCl4+H2O→NoReaction

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