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in Physics by (80.8k points)

B1, B2, B3, and B4 are identical light bulbs. There are six voltmeters connected to the circuit as shown. All voltmeters are connected so that they display positive voltages. Assume that the voltmeters do not affect the circuit.

If B2 were to burn out, opening the circuit, what would happen to the reading of V1? Let V be its original reading when all bulbs are functioning and let V be its reading when B2 is burnt out.

1 Answer

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by (52.5k points)
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Best answer

The correct option is: (D)

Explanation:

With B2 burning out, the total resistance of the circuit increases as it is now a series circuit. This decreases the current in the main branch, decreasing V1. For V1 to be halved, the current must be halved which means the total resistance must be doubled, which by inspection did not happen in this case (total before = 5/3 R, total after = 3 R)

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