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If sin A = 3/4, calculate cos A and tan A.

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Solution
Given sinA=3/4
Or p/h=3/4
Let  p=3k and h=4k
Now By Pythagoras theorem
p2 + b2 =h2
9k2 + b2 =16k2

b2 = 7k2
Or  b=+k√7
Now CosA=b/h=√7/4
Now tanA=SinA/CosA=3/√7

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