(b) y = 2x - 5x2
Explanation:
Given, \(\vec{u}\) = \(\hat{i}+2\hat{j}\) = ux\(\hat{i}\) + uy\(\hat{j}\)
Then ux = 1 = ucosθ and
uy = 2 = usinθ
\(\therefore\) tanθ = \(\frac{u\sin\theta}{u\cos\theta}\) = \(\frac{2}{1}\) = 2
The equation of trajectory of a projectile motion is
y = x tanθ - \(\frac{gX^2}{2u^2\cos^2\theta}\)
= x tanθ - \(\frac{gX^2}{2(u\cos\theta)^2}\)
\(\therefore\) y = x * 2 - \(\frac{10\times X^2}{2(1)^2}\)
= 2x - 5x2