Fewpal
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Given sec θ = 13/12, calculate all other trigonometric ratios.

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Solution:
Given sec θ=13/12
Or
H/B=13/12
let H=13K ,B=12K
So in a right angle triangle with angle A
P2 + B2 =H2
P=5k
sin θ = P/H = 5/13
Cos θ = B/H = 12/13
Tan θ = P/B = 5/12
Cosec θ= 1/sin θ = 13/5
cot θ = 1/tan θ = 12/5

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