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in Laws of Motion and Friction by (24.0k points)
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A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and the floor is (g = 10 m/s2)

(a) 2.8 N

(b) 2 N

(c) 8 N

(d) zero

1 Answer

+1 vote
by (34.3k points)
edited by
 
Best answer

Correct option (a) 2.8 N

Explanation :

The applied force of 2.8 N is less than fms (= 8 N) and as such the block does not move. When the block is at rest. frictional force = applied force  = 2.8 N

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