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+1 vote
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in Chemistry by (20 points)
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In complex MCl3.5H2O, the secondary valency of metal is 6 and it has no molecule of water present out of coordination sphere. Calculate the volume of 0.1M AgNO3 solution needed to precipitate the free chloride ions in 200 mL of 0.01 M solution of the complex.

(a) 80mL

(b) 40mL

(c) 20mL

(d) 120mL

PS- The answer is (b) 40mL 

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1 Answer

+1 vote
by (44.0k points)

Correct option is (b) 40ml

As we have given,

The secondary valency of metal = 6

and There is no molecule of water present out of coordination sphere.

Therefore--

Molecular formula of complex will be---

[M(H2O)5Cl]Cl2

In solution 1 mole of [M(H2O)5]Cl2 gives 2 mole

of chloride ions.

\(\therefore\) 2 mole [M(H2O)5Cl]Cl2 gives = 4 mole chloride ions.

Let say V volume of 0.1 M AgNO3 needed to precipitate free chloride ions present in 200 ml of 0.01 M

[M(H2O)5Cl]Cl2.

\(\therefore\) 0.1 x V = 2 x(200ml x 0.01)

V = 4/0.1

V = 40 ml

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