Correct option is (b) 40ml
As we have given,
The secondary valency of metal = 6
and There is no molecule of water present out of coordination sphere.
Therefore--
Molecular formula of complex will be---
[M(H2O)5Cl]Cl2
In solution 1 mole of [M(H2O)5]Cl2 gives 2 mole
of chloride ions.
\(\therefore\) 2 mole [M(H2O)5Cl]Cl2 gives = 4 mole chloride ions.
Let say V volume of 0.1 M AgNO3 needed to precipitate free chloride ions present in 200 ml of 0.01 M
[M(H2O)5Cl]Cl2.
\(\therefore\) 0.1 x V = 2 x(200ml x 0.01)
V = 4/0.1
V = 40 ml