Question

The binding energy per nucleon of deuteron (₁H²) and helium atom (₂He⁴) is 1.1 MeV and 7 MeV respectively. If two deuteron atoms react to forrn a single helium atom, the released energy, is

(a) 13.9 MeV

(b) 26.9 MeV

(c) 23.6 MeV

(d) 19.2 MeV

Answer 1

The correct option is (c) 23.6 MeV.

Explanation:

Given : Binding energy per nucleon of deuteron (₁H²) = 1.1 MeV 

Binding energy per nucleon of helium ₂He⁴ = 7 MeV. 

Total binding energy of two deuteron atoms (₁H²) (1p + 1n) = 2 (2 x 1.1) =4.4 MeV. 

Total binding energy of helium atom (₂H⁴) (2p + 2n) = 4 x 7  = 28 MeV. 

Therefore energy released on forming helium nucleus from two deuterons = 28 - 4.4 = 23.6 MeV.