Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
2.7k views
in Physics by (79.0k points)

In an LCR circuit as shown in figure, both switches are open initially. Now. switch S1 is closed. S2 kept open. (q is charge on the capacitor and  τ = RC is capacitive time constant). Which of the following statement is correct?

(a) At  t = τ/2, q = CV(1-e-1)

(b) Work done by the battery is half of the energy dissipated in the resistor

(c)  AT t = τ , q = CV/2

(d) AT t = 2τ, q = CV(1-e-2)

1 Answer

+1 vote
by (50.7k points)
selected by
 
Best answer

Correct option (d) AT t = 2τ, q = CV(1-e-2)

Explanation:

As switch S1 is closed and switch S2 is kept open. Now, capacitor is charging through a resistor R. Charge on a capacitor at any time t is

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...