Construction of ΔABC, given the perimeter (AB + BC + CA) = 'a' cm, ∠B = x° and ∠C = y°.
Steps of construction:
Step 1: Draw the line segment XY = 'a' cm.
Step 2: Draw the ray XL at X making an angle of x° with XY.
Step 3: Draw the ray YM at Y making an angle of y° with XY.
Step 4: Draw angle bisector of ∠LXY.
Step 5: Draw angle bisector of ∠MYX such that it intersects the angle bisector of ∠LXY at a point A.
Step 6: Draw the perpendicular bisector of AX such that it intersects XY at a point B.
Step 7: Draw the perpendicular bisector of AY such that it intersects XY at a point C.
Step 8: Join AB and AC.
Thus, ABC is the required triangle.
