Question

find the equation of a circle with origin as centre and which circumscribes an equilateral triangle whose median is of length 3a

Answer 1

For equilateral triangle

Height = median =3a

So radius of the circle=2/3×3a=2a

Centre of the circle =(0,0)

Hence equation of the circle.

(x-0)^2+(y-0)^2=(2a,)^2

=>x^2+y^2=4a^2