Let the first term of an A.P = a
and the common difference of the given A.P = d
As we know that
an = a+(n-1) d
a4 = a +( 4-1) d
a4 = a+3d
Similarly ,
a8 = a + 7 d
a6 = a + 5 d
a10 = a+ 9d
Sum of 4th and 8th terms of an A.P = 24 ( given )
a4 +a8 = 24
a + 3d + a + 7d = 24
2a + 10 d = 24
a +5d = 12 .....................(i)
Sum of 6 th and 10 th term of an A.P = 44 ( given )
a6 +a10 = 44
a + 5d +a+ 9d = 44
2a + 14 =44
a + 7d = 22 .....................(ii)
Solving (i) & (ii)
a +7 d = 22
a + 5d = 12
2d = 10
d = 5
From equation (i) ,
a + 5d = 12
a + 5 (5) = 12
a+25= 12
a = - 13
a2 = a+d = -13+5 = -8
a3 = a2 + d = -8+5 = -3
So, the first three terms are -13 ,-8,-3