Correct Answer - Option 2 : 471.57 kg/m

^{3} and 15 kg/s

**Concept:**

Let us assume that the tank is cylindrical.

Volume of tank = \(\frac{\pi}{4}d^2h\)

Density of liquid = \(\frac{Mass}{Volume}\)

Mass flow rate = Density × Volume flow rate

**Calculation:**

**Given:**

Q = 0.032 m3/s, d = 1.5 m, h = 4.20 m

Volume of tank = \(\frac{\pi}{4}d^2h\)

Volume of tank = \(\frac{\pi}{4}× 1.5^2× 4.2=7.418\;m^3\)

Density of liquid = \(\frac{Mass}{Volume}\)

Density of liquid = \(\frac{3500}{7.418}=471.80\;kg/m^3\)

Mass flow rate = Density × Volume flow rate

Mass flow rate = 7.418 kg/m^{3} × 0.032 m3/s

Mass flow rate = 15.097 kg/sec