Correct Answer - Option 2 : 471.57 kg/m
3 and 15 kg/s
Concept:
Let us assume that the tank is cylindrical.
Volume of tank = \(\frac{\pi}{4}d^2h\)
Density of liquid = \(\frac{Mass}{Volume}\)
Mass flow rate = Density × Volume flow rate
Calculation:
Given:
Q = 0.032 m3/s, d = 1.5 m, h = 4.20 m
Volume of tank = \(\frac{\pi}{4}d^2h\)
Volume of tank = \(\frac{\pi}{4}× 1.5^2× 4.2=7.418\;m^3\)
Density of liquid = \(\frac{Mass}{Volume}\)
Density of liquid = \(\frac{3500}{7.418}=471.80\;kg/m^3\)
Mass flow rate = Density × Volume flow rate
Mass flow rate = 7.418 kg/m3 × 0.032 m3/s
Mass flow rate = 15.097 kg/sec