Work done in isothermal expansion = W =
where, R = 0.0821 atm/mol/K
T = PV/nR
= 4× 105 N/m² × 1L/1 × 0.0821 K
= (4 × 105/0.0821) K
= 4/1 = 4
Hence, W = 2.303 × 0.0821 × 4 × 105/0.0821 × log4
= 2.303 × 4 × 105 log4
= 5.54 × 105 J
= 554 × 10³ J
= 554 kJ
so the answer of this question is 554KJ
HOPE YOU UNDERSTOOD