The correct option is: (B) -490
Explanation:
We have, Tn = (7 -3n)
First term, T1 = (7 -3 x 1) = 4
Second term, T2 = 7 - 3 x 2= 1
Third term, T3 = 7 -3 x 3 = -2
.'. Series is 4, 1, - 2, ..........
and common difference = -3
Sum of first 20 terms (S20)
= 20/2[2 x 4 + (20 - 1)(-3)] = 10[8 - 57] = -490