Correct Answer - Option 4 :
±250 μs
Concept:-
Total errors = Error due to 0.005% accuracy of reading + error due to ±1 in the final digit.
Calculation:-
error due to 0.005% of reading
= 0.005% × 05000000 μs
= 250 μsec.
Error due to ±1 final digit
\(=\pm1\times\frac{1}{10^8}\)
\(\rm [Resolution=\frac{1}{10^n}]\)
= 0.01 μsec
Total error = 250 + 0.01 μsec
= 250.01 μsec.