Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56 views
in Aptitude by (102k points)
closed by
Biswas takes 12 days more than Ashit to complete the particular work. Biswas and Ashit start the work and Ashit leaves the work 12 days before the work is completed. Biswas completes 60% of the overall work. Had Biswas worked independently, the amount of time taken by him to complete the whole work is:
1. 24 days
2. 36 days
3. 12 days
4. 18 days
5.

1 Answer

0 votes
by (103k points)
selected by
 
Best answer
Correct Answer - Option 2 : 36 days

CALCULATION:

If Ashit takes 'a' days to complete the whole work, then Biswas will take (a + 12) days to complete the whole work.

As Biswas has completed 60% of the work, the remaining 40% work is completed by Ashit. 

∵ Ashit has done 40% of the work before leaving.

∴ Ashit has worked for 2a/5 days.

∵ Biswas has completed 60% of the total work

∴ Biswas has worked for [3(a + 12)]/5 days.

But as Ashit leaves the work 12 days before the Biswas.

⇒ No. of days for which Biswas works = No. of days for which Ashit works + 12 

⇒ [3(a + 12)]/5 = (2a/5) + 12

⇒ 3a + 36 = 2a + 60

⇒ a = 24 days

∴ Time taken by Biswas to complete the work independently = (a + 12) = (24 + 12) = 36 days

  • The key to solving this problem is to start from work completed by Biswas.
  • The time taken to complete the work ∝ Amount of work.
  • Efficiency ∝ 1/Time Taken to complete the work.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...