Question

The average kinetic energy of a gas molecules at 27°C is 6.21 x 10^-21 J. Its average kinetic energy at 227°C will be

(a) 10.35 x 10^-21 J

(b) 52.2 x 10^-21 J

(c) 5.22 x 10^-21 J

(d) 11.35 x 10^-21 J

Answer 1

Correct option (a) 10.35 x 10^-21 J

Explanation :

The average K.E of a gas molecules at temperature T is given by K = (3/2)k_BT