Correct Answer - Option 4 : Seven times the seventh term.
Calculation:
Let 1/p and 1/q are fourth and eighth term of HP
⇒ 1/p = 2/q
p and q are in AP
p = a + 3d
q = a + 7d
∴ 1/(a + 3d) = 2/(a + 7d)
⇒ a + 7d = 2a + 6d
⇒ d = a
The nth term in HP = 1/(a + (n - 1)d)
⇒ 1/na
The nth term in HP = First term/n
First term = n × nth term
Option 4 is correct
The reciprocals of the terms in an HP will form an AP.