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The least multiple of 7 which leaves the remainder 4 when divided by each of 6, 9, 15 and 18 is
1. 182
2. 350
3. 364
4. 455
5.

1 Answer

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Correct Answer - Option 3 : 364

LCM of 6, 9, 15, 18 is 90.

Let the number is (90k+4),which is multiple of 7.

Put the value of k=1, 2, 3, 4, 5....

Put k = 1

⇒ (90×1 + 4) = 94

⇒ 94\7, remainder = 3

Put k = 2 

⇒ (90×2 + 4) = 184

⇒ 184\7, remainder = 2

Put k = 3

⇒ (90×3 + 4) = 274

⇒ 274\7, remainder = 1

Put k = 4

⇒ (90×4 + 4) = 364

⇒ 364\7, remainder = 0

 ∴ 364 is the least multiple of 7 which leaves 4 as remainder when divided by each of 6, 9, 15 and 18 .

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